luas segitiga ABCadalah 200 cm².jika tingginya 25 cm , berapa panjang alas segitiga ABC
[tex] = \frac{luas \times 2}{t} [/tex]
[tex] = \frac{200 \: {cm}^{2} \times 2}{25 \: cm} [/tex]
[tex] = \frac{400 \: {cm}^{2} }{25 \: cm} [/tex]
= 16 cm
『Answer by Vi⊹࿐』